Question

A train takes 5 hour to reach station B from station A and then 6 hour to return to station A from station B.

The distance between the two stations is 300 km. Find (i) the average speed, (ii) the average velocity of the

train.solve this​

Answer 1

Given :

• A train takes 5 hour to reach station B from station A and then 6 hour to return to station A from station B. The distance between the two stations is 300 km

To find :

• (i) the average speed

• (ii) the average velocity of the

Solution :

I) Average speed = Total distance/total time

Average speed = 300+300/5+6

= 600/11

= 54.54 km/hr

∴ Average speed is the 54.54 km/hr

II) Average velocity = displacement/time

through it's comes back to its original position it do not have displacements

then ,

∴ Average velocity is 0

Some other Formulas :

• Speed = d/t

• F = m. a

• a (bar) = v - v_0/t = Δv/Δt

• w = F x d

• P = W/Δt

• V = 1R

• PE = mgh

• p = mv

Answer 2

Answer:

If your Question was this;

A train takes 2 h to reach station B from station A, and then 3 h to return from station B to station A. The distance between the two stations is 200 km. Find : (i) the average speed, (ii) the average velocity of the train.

Then your answer is;

Total distance   D=200+200=400 km

Average speed    ∣ V  avg  ∣=  Total distance/ Total time  

∴ ∣ V  avg  ∣= 400 /2+3 =80 km/h

Displacement   S=0

Average velocity  V  avg  = Total displacement /Total time

​∴ V  avg  =  0 km/h