A train towe: from one station to another in two hours ome. Its speed-time
praph during the motion is shown in Fig.
(0)
Determine the maximum acceleration during the journey
(10)
Also calculate the distance covered during the time interval 0.75 hour to 1
hour.
Ans: () 120 kmh
61) 8.75 km
Answers
Answered by
3
Answer:
Maximum acceleration will occur in the region with maximum slope.
From the given curve region CD is having the maximum curve.
Thus, maximum acceleration=
change in distance
change in velocity
=
0.25
60−20
=160
Now, total area under the curve between 0.75 to 1.00 hrs is given by
(
2
1
×0.25×40)+(20×0.25)=10km
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