A train travel 360 km at a uniform speed. if the speed had been 5km/h more , it would have taken 1hours less for the same journo. find the speed of the train.
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The speed and the time are treated as xand3y.
The new speed and time will be x+5 and y-1 and xy+5y-x and x*y are equal so 5y-x=0.
In other words 1x=5y.
The product of 1x and 1y are 360.
The product of 1x and 0.2x are 360
the value of x^2 is 1800
so 42 km/h
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