a train travel 360km at a uniform speed.if the speed had been 5km/h more it would be taken 1 hour less for the same journey .find the speed of the train
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speed of train= xkm/hr
case 1:time taken =360x (1)
case 2 : speed of train =(x+5)km/hr
time=360x+5 (2)
acc to question
360x+5=360x−1
360x=360x+1800−x2−5x
x2+5x+1800=0
x2+45x−40x−1800=0
x(x−40)+45(x−40)=0
(x−40)(x+45)=0
x=−45&40
speed cant be negative so, sped of train is 40km/hr
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