Question

a train travel a distance of 1000 km 400 m in 31/2 hours 30 min. what is the average speed of the train

Answer 1

total distance=1000000+400
=1000400
time=31/2*3600+30*60
=31*1800+1800
=1800(31+1)
=1800*32
=57600
speed=d/t
=1000400/57600
=10004/576

Answer 2

Answer:

62.525 km/hr .

Step-by-step explanation:

Distance traveled by train = 1000 km 400 m

1000 m = 1 km

So, $1 m = \frac{1}{1000}km$

So, $400 m = \frac{400}{1000}km$

$400 m =0.4 km$

So, Distance traveled by train = 1000 km + 0.4 km =1000.4 km

Time = 31/2 hours 30 min.

60  min = 1 hour

So, $1 min = \frac{1}{60} hour$

So, $30 min = \frac{30}{60} hour$

So, $30  min =0.5 hour$

So, Time = 31/2 +0.5 =16 hours

Speed = $\frac{Distance}{Time}$

Speed = $\frac{1000.4 }{16}$

Speed = $62.525$

Hence the speed of the train is 62.525 km/hr .