a train travel at a certain average speed for a distance of 54km and then travels a distance of 63km at an average speed of 6km/hr more than the first speed.if it take 3 hours to complete the total journey,what is its original speed
shujatmehdi453p1tpwa:
Pliz do fast
Answers
Answered by
0
54×63=3402
3402×3=10207
3402×3=10207
True or not
Answered by
3
Hey friend.....
Distance =54km
Let the average speed be x
Distance =63 km
The average speed to cover this distance =x+6
Total time taken =3hr
D/S=t
∴54/x+63/x=3
54(x+6)+63xx(x+6)/x(x+6)=3
54x+324+63x=3x2+18x
=> 3x2−99x−324=0
=> x2−33x−108=0
(x−36)(x+3)=0
x=36or−3
x=−3 is not admissible
Hence x=36km/hr is the speed
Distance =54km
Let the average speed be x
Distance =63 km
The average speed to cover this distance =x+6
Total time taken =3hr
D/S=t
∴54/x+63/x=3
54(x+6)+63xx(x+6)/x(x+6)=3
54x+324+63x=3x2+18x
=> 3x2−99x−324=0
=> x2−33x−108=0
(x−36)(x+3)=0
x=36or−3
x=−3 is not admissible
Hence x=36km/hr is the speed
Thanks
welcome
Similar questions