A train travel his 2/7 part of his distance and his speed is decreased 21.66% so train reached in his destination late by 65 minutes. find the total distance traveled by train.
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a train after covering 2/7 part of its distance reduced its speed by 21.66 % so the train reached in its destination late by 65 minutes.
To find : the present time taken by train to cover the complete distance.
solution : let total distance is x , speed = v and time taken = t
so, x/v = t .....(1)
2/7 part of distance covered by train with speed v and 5/7 part of distance covered by train with speed v - 21.66% of v = 0.7834v
so, 2x/7v + (5x/7)/(0.7834v) = t + 65/60
⇒2/7 t + (5/7 × 0.7834) t = t + 65/60 [ from equation (1) ]
⇒0.29t + 0.91t = t + 1.083
⇒t = 5.415 hrs = 5 hrs + 0.415 × 60 min ≈ 5 hrs 25 minutes
Therefore the present time taken by the train to cover the complete distance = 5 hrs 25 minutes
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