A train traveling along a straight track with a speed of 2 ms-1, begins to accelerate with a=2/v ms^-2
where v is in ms-1. Find its velocity after 3 seconds in m/s.
Answers
Answer:
8ms-1
Explanation:
The acceleration of an object can be calculated by the formular
A=(vf-vi)/Tf-Ti)
Where A =Acceleration
Vf=Final velocity
Vi= Initial velocity
Ti=Initial Time
Tf =Final Time
In this case,
A=2/V ms -2
Vi=2ms-1
Ti-Tf we are given as 3 seconds
Therefore to find Vf after three seconds, We assume that;
Vf= X
Replacing Vf in the formular
2=(x-2ms-1)/3
6=x-2
x=8
Replacing x with Vf
Vf=8
Answer:
The formula for calculating the acceleration of an object is, A= (vf-vi)/ (Tf-Ti)
Where Vi = Initial velocity
Vf = Final velocity
Ti = Initial Time
Tf = Final Time.
In this case,
A= 2/V ms -2
Vi = 2ms – 1
Given, Tf- Ti = 3 secs.
If we take “x” as the final velocity, then Vf= x
Therefore, we get the equation,
2 = (x-2ms-1)/ 3
6 = x-2
X = 8.
Therefore, the final velocity is 8m/s.