A train traveling at 27km /hours is accelerating at 0.5m /s² what is the distance traveled by the train in 12 second
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0
Answer:
96 meters
Explanation:
speed=27 km/h =7.5 m/s
acceleration = 0.5 m/s²
time = 12 s
2nd equation of motion: s=vt+at²/2
putting the values we get distance s =96 m
Answered by
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here
u= 27km/hr
t=12sa=0.5
We know
s=ut+1/2at^2
27x12+1/2x0.5x12x12
324+36
360
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