a train traveling at 72km/hr is stopped in 4 sec. by the application of brakes. What is retardation of the train
Answers
Answered by
15
72×1000/3600=20 m
a=v-u/t
a=0-20/4
a= -5m/s^2
a=v-u/t
a=0-20/4
a= -5m/s^2
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Answered by
2
hey dear your answer is here..
_____________________
u=72km/h= 72×5÷18=20m/s
t=4sec
v=0
a=(v-u)÷t
a=(0-20)÷4
a=-5m/s^2
_____________________
u=72km/h= 72×5÷18=20m/s
t=4sec
v=0
a=(v-u)÷t
a=(0-20)÷4
a=-5m/s^2
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