Question

A train traveling at a speed of 72km/h comes to rest in 10 seconds. Its acceleration is

Answer 1

Answer:

Initial velocity (u)=72km/h =72000m/3600s=20m/s

final velocity (v)=0m/s

time (t)=10s

let the acceleration=a

from the relation we know

a=(v-u)/t

=(0-20)/10

=. -20/10

=. -2.0m/s(squre)

Explanation:

here - sign represent retardation.