Math, asked by prashunkumar41, 4 months ago

A train traveling at a uniform speed passes by a platform 220 m long in 30 s and another platform 325 m long in 39 s Find.
(i) the length of train and the speed of train
I need a answer with process if you have no process don't answer otherwise your answer will be reported​

Answers

Answered by Anonymous
4

Step-by-step explanation:

Given s = t + 220/30 ... (i)

and s = t + 325/39 ... (ii)

Solving (i) and (ii), we get

39(t + 220) = 30(t + 325)

39t + 8580 = 30t + 9750

9t = 1170

t = 130 m

Put in (i), we get

Speed = 130 + 220/30

= 350/30

= 11.66 m/sec

S = 3600 × 11.66/1000

hope it's help you...

Answered by VarshatheRowdy2
2

Step-by-step explanation:

Given

s = t + 220/30 ... (i)

and s = t + 325/39 ... (ii)

Solving (i) and (ii), we get

39(t + 220) = 30(t + 325)

39t + 8580 = 30t + 9750

9t = 1170

t = 130 m

Put in (i), we get

Speed = 130 + 220/30

= 350/30

= 11.66 m/sec

S = 3600 × 11.66/1000

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