A train traveling south leaves the station at a constant rate of 62 kilometers per hour. A secound train traveling north leaves the station at the same time traveling at a constant rate of 68 kilometers per hour. How many hours after the trains leave will they be 455 kilometers apart.
A.) 3.5
B.) 4.5
C.) 5.5
D.) 6.5
Answers
Answered by
5
Velocity of train A=Va=62 kmph
Velocity of train B=Vb=65 kmph
Relative velocity=Va+Vb
=62+68
=130 kmph
Time = Distance / speed
=455 / 130
=3. 5 h
Velocity of train B=Vb=65 kmph
Relative velocity=Va+Vb
=62+68
=130 kmph
Time = Distance / speed
=455 / 130
=3. 5 h
Answered by
1
Answer:
A.) 3.5
Step-by-step explanation:
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