a train travelled a certain distance at a uniform speed.if the train had been 6km/hr faster it would have taken 8 hrs less than the scheduled time and if the train were slower by 6 km/hr it would have taken 12 hour more than the scheduled time find the length of the journey
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Answer:
1440 Km
Step-by-step explanation:
Let say length of Journey = L km
Let say scheduled time = T Hr
Scheduled speed = S km/hr
L = ST
L = (S + 6)(T-8)
L = (S -6)(T + 12)
ST -8S +6T -48 = ST + 12S -6T -72
20S = 12T + 24
5S = 3T + 6. Eq1
ST = ST + 12S -6T -72
12 S = 6T + 72
6S = 3T + 36. Eq2
Eq2-eq1
S = 30
5*30 = 3T + 6
T = 144/3
T = 48
L = ST = 30*48 = 1440 km
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