Math, asked by vedant03patil, 6 months ago

A train travelled a certain distance of the speed of 20 Km/hr. Another train B travelled

for 50 km less than train A at the speed of 30 km/hr and took 10 hours less than train A

to reach its destination. What were the distances that both the trains travelled?​

Answers

Answered by SKSTUDYPOINTSILIGURI
0

Have a look !!

Let distance travelled by A = x km

So, distance travelled by B = x - 50 km

Speed of A = 20 kph

Speed of B = 30 kph

Time taken by A = Distance / Speed = x / 20 hr

Time taken by B = Distance/Speed = ( x -50)/ 10 hr

B.Q.

( x -50)/ 10 - x / 20 = 10

=> ( 2x - 100 - x ) /20 = 10

=> ( x- 100 ) / 20 = 10

=> x- 100 = 10× 20 = 200

=> x = 200 + 100 = 300

So, distance travelled by A = x km = 300 km

So, distance travelled by B = x - 50 km

= (300 - 50) km

= 250 km

HOPE IT HELPED

ENJOY MATHS !!!

(SK STUDY POINT SILIGURI)

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