Question

A train travelling
a 27km ph is accelarated at th
0.5ml să What is the distance travelled
by train 12sec ​

Answer 1

Given

Initial Velocity,u=27 Km/h=7.5m/s

Acceleration,a=0.5m/s²

Final Velocity,v=?

Distance,s=?

Using First equation of motion,

v=u+at

v=7.5+0.5x12

v=7.5+6

v=13.5

Now, Using Third Equation Of Motion

v²=u²+2as

13.5²=7.5²+2(0.5)s

13.5x13.5=7.5x7.5+2(0.5)s

182.25=56.25+2x0.5xs

182.25=56.25+s

56.25+s=182.25

s=182.25-56.25

s=126m

Therefore,the train travelled 126m in 12 seconds..

Hope This Helps You ;)