Question

A train travelling at 20 m per second accelerated 0.5 m per second square for 30 second how far will it cover in this time

Answer 1

Hey mate!

Here's your answer!!
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Initial velocity 【u】 = 20m/s

Acceleration 【a】 = 0.5 m/s

Time 【t】= 30 sec


Now, by using the second equation of motion,

$s = ut + \frac{1}{2} at {}^{2}$

We, have it as...

$s = 20 \times 30 + \frac{1}{2} \times 0.5 \times (30) {}^{2}$

$s = 825 \: m$

∴ It will cover 825 m in this time.
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Hope it helps you!!

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