Question

A train travelling at 20 m per second accelerates at 0.5 metre per second square for 30 seconds how far it will travel in this time​

Answer 1

Answer:

825 m

Explanation:

Given :

Initial velocity ( u ) = 20 m / sec

Acceleration ( a ) = 0.5 m / sec²

Time ( t ) = 30 sec .

We have to find distance ( s ) :

From second equation of motion we have :

s = u t + 1 / 2 a t²

Putting values here :

s = 20 × 30 + 1 / 2 × 0.5 × 30 × 30

s = 600 + 0.5 × 15 × 30

s = 600 + 225

s = 825 m

Thus the train will cover 825 m distance .

Answer 2

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Distance\:travelled=825\:m}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a train travelling at 20 m per second accelerates at 0.5 metre per second square for 30 seconds.

• We have to find how far it will travel in this time.

$\underline \bold{Given : } \\ \implies Initial \: velocity(u) = 20 \: m/s \\ \\ \implies Acceleration(a) = 0.5 \: m /{s}^{2} \\ \\ \implies Time(t) = 30 \: sec \\ \\ \underline \bold{To \: Find : } \\ \implies Distance \: travelled(s) = ?$

• According to given question :

$\bold{By \: third \: equation \: of \: motion : } \\ \implies s = ut + \frac{1}{2} {at}^{2} \\ \\ \bold{putting \: given \: values} \\ \implies s = 20 \times 30 + \frac{1}{2} \times \frac{1}{2} \times 30 \times 30 \\ \\ \implies s = 600 + 225 \\ \\ \bold{\implies s = 825 \: m} \\ \\ \bold{\therefore Distance \: travelled \: by \: train \: is \: 825 \: m}$