Question

a train travelling at 20 m s -1 accelerates at 0.5 m s-2 for 30 sec. how far will travel in this time​

Answer 1

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Answer 2

Given:

• Initial velocity, u = 20m/s
• Time taken, t = 30 s
• Acceleration, a = 0.5m/s^2

To Find:

• Distance travelled by the train ?

Solution:

By applying second equation of motion,

$\star\;{\boxed{\sf{\purple {ut + \dfrac{1}{2} a{t}^2}}}}$

Putting the values,

$:\implies\sf 20 \times 30 + \dfrac{1}{2} \times 0.5 \times 30 \times 30$

$:\implies\sf 600 + 225$

$:\implies{\boxed{\frak{\pink{ 825\;m }}}}\;\bigstar$

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$\boxed{\substack{\displaystyle \sf \star v=u+at \\\\ \displaystyle \sf \star \: \: s = ut+\dfrac{1}{2}at^2 \\\\ \displaystyle \sf \star \: \: 2as=v^2-u^2}}$