A train travelling at 20 m/s accelerate at 0.5m/s2 for 30 seconds. How far will it
travel in this time.
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Answer:
Explanation: Initial velocity of the train(u) = 20m/s
Acceleration of the train(a) = 0.5m/s²
Time taken(t) = 30 sec
Now we have to distance(s) travelled using the second equation of motion :
s = ut + 1/2 at²
s = 20(30) + 1/2(5/10)(30)(30)
s = 600 + 1/4 (900)
s = 600 + 225
s = 825
therfore the car travelled 825 m in 30 sec
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