Question

A train travelling at 20 metre per second silver rate at 0.5 metre per second square from 30 second how far will it travel in this time ?

Answer 1

Given :-

▪️Initial velocity = 20 m/s

▪️Acceleration = 0.5 m/s² = 1/2 m/s²

▪️Time = 30 sec

Now we have to find out the distance travelled in 30 sec during the period of Acceleration.

As we have

S = ut + 1/2 at²

→ S = 20(30) + 1/2 × 1/2 × 30²

→ S = 600 + 1/4 × 900

→ S = 600 + 225

→ S = 825 m

So train will travel 825m.