Question

A train travelling at 20m s-1 accelerates at 0.5m s-2 for 30s . How far it travel in this time?​

Answer 1

Explanation:

Just Comparing both's acceleration Then We will Find The Distance

Answer 2

$\sf \pmb{Answer :}$

Given:-

• Initial velocity of car (u) = 20m/s

• Acceleration of the car (a) = 0.5m/s²

• Time Taken by car (t) = 30s

To Find:-

Distance (s) travel by car in this time.

Solution:-

By using 2nd equation of motion

⟹ s = ut +1/2at²

Put the values which is given above

⟹ s = 20×30 + 1/2 ×0.5×30²

⟹ s = 600 + 0.5 ×15 ×30

⟹ s = 600 + 7.5 × 30

⟹ s = 600 + 225

⟹ s = 825m

∴ The Distance travel by car in this time is 825m.

Additional Information !!

Some equation of motion are

⟹ v = u +at

⟹s = ut +1/2at².

⟹ v² = u² + 2as

Here,

• v is the final velocity
• u is the initial velocity
• a is the acceleration
• s is the displacement or Distance
• t is the time taken