Question

A train travelling at 20m/s accelerates at 0.5m per second square for 30s how far will it travel in this time

Answer 1

Answer:

Explanation:

Given :-

Initial speed, u = 20 m/s

Acceleration, a = 0.5 m/s²

Time taken, t = 30 sec

To Find :-

Distance traveled

Formula to be used :-

2nd equation of Motion,

s = ut +(1/2) at²

Solution :-

Putting all the values, we get

s = ut +(1/2) at²

s = 20 × 30 + (1/2) × 0.5 × (30)²

s = 825 m

Hence, the distance traveled by train is 825 m.

Answer 2

Answer:

Concept:

Distance is a numerical representation of the distance between two objects or points. A physical length or an approximation based on other physics or common usage criteria might be referred to as distance. The distance between two points A and B is sometimes written as. The terms "distance from A to B" and "proximity from B to A" are comparable in most situations. A metric, or distance function, is a mathematical expansion of the effects of physical distance. it is a way of explaining what it means for elements of a space to be "near to" or "far away" from one another.

Given:

For 30 seconds, a train travelling at 20 mph accelerates at 0.5 metre per second square. How far will it go in this amount of time?

Find:

find the answer for the given question

Answer:

The length of the spline connecting two places is called the distance between them. In coordinate geometry, the length of the reference line connecting the supplied coordinates could be used to find the path between two points. The migrating by a body to get there from an initial location to an end point in a certain amount of time and at a given velocity is known as the distance travelled. Distance = time * velocity. d = v*t if the velocity is constant.

Initial velocity $=20$

acceleration $= 0.5$

time $= 30$

$S= ut + (1/2) at^2$

  $=(20*30)+1/2 * 0.5* (30)^2$

  $= 600+ 225$

  $= 825 m$

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