A train travelling at 20m/s accelerates at 0.5m per second square for 30s. How far will it travel in this time?
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Given :
Initial velocity of train, u = 20 m/s
Acceleration of train, a = 0.5 m/s²
Time taken, t = 30 s
To find :
Distance travelled in this time.
Solution :
1st equation of motion -
⇒ v = u + at
⇒ v = 20 + 0.5 × 30
⇒ v = 20 + 15
⇒ v = 35 m/s
∴ Final velocity of train, v = 35 m/s.
Now, using 3rd equation of motion -
⇒ v² = u² + 2as
⇒ 35² = 20² + 2 × 0.5 × s
⇒ 1225 = 400 + 1 × s
⇒ 1225 - 400 = s
⇒ s = 825 m
∴ The train will travel 825 m of distance in this time.
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