Question

A train travelling at 20m/s accelerates at 0.5m/s^2 for 30 seconds. How far will it travel in this time

Answer 1

Answer:-

S = 825 m

Given :-

u = 20 m/s

a = 0.5 m/s²

t = 30s

To find :-

The district travelled.

Solution :-

As we have equation of motion for solving this kinds of problem.

From second equation of motion we have :-

★ $\boxed{\sf{S = ut + \dfrac{1}{2}at^2}}$

→$S = 20 \times 30 + \dfrac{1}{2}\times 0.5 \times (30) ^2$

→$S = 600 + \dfrac{1}{2}\times 0.5 \times 900$

→$S = 600 + 0.5 \times 450$

→$S = 600 + 225$

→$S = 825 m$

hence,

Distance covered will be 825 m.

Answer 2

Answer:

Distance travelled in this time =

825 meter

Explanation:

given that,

A train travelling at 20m/s accelerates at 0.5m/s^2 for 30 seconds.

here,.

we have,

initial velocity of the train will be 20 m/s

and

acceleration produced in the train = 0.5 m/s²

time taken for acceleration = 30 seconds,

now,

we have,

initial velocity(u) = 20 m/s

acceleration(a) = 0.5 m/s²

time taken(t) = 30 seconds

by the equation of motion,

S = ut + ½ at²

where,

S = distance travelled during acceleration

putting the values,

S = 20(30) + ½ (0.5)(30) × 30

S = 600 + 225

S = 825 m

so,

Distance travelled in this time

= 825 meter