Question

A train travelling at 27km/h is accelerated at the rate of 0.5m/s^2.what is the distance travelled by the train in 12 seconds.

Answer 1

Given:-

• Speed of train or initial velocity = 27 km/h

• Acceleration of the train = 0.5 m/s²

• Total time taken by train = 12 s

To Find:-

• Distance travelled by train in 12s = ?

Solution:-

• To calculate the distance travelled by train , at first we have to change the initial velocity into m/s then we use a formula to calculate the distance travelled by train. We use second equation of motion.

Formula Used:-

==> S = u t + 1/2 a t²

==> Initial velocity = 27 × 5/18

==> Initial velocity = 15/2 m/s

Let's Find out distance here:-

• As per 2nd equation of motion:-

==> S = Ut + 1/2 a t²

• S = Distance , t = Time, U = initial velocity

==> S = 15/2 × 12 + 1/2 × 0.5 × (12)²

==> S = 15 × 6 + 1/2 × 0.5 × 12 × 12

==> S = 90 + 0.5 × 6 × 12

==> S = 90 + 0.5 × 72

==> S = 90 + 36

==> S = 126 m

Hence,

• Distance travelled by train in 12s= 126 m

Answer 2

Question:-

• A train travelling at 27km/h is accelerated at the rate of 0.5m/s² . What is the distance travelled by the train in 12 seconds.

To Find:-

• Find the distance travelled by train in 12 seconds.

Solution:-

Given ,

• Train travelling at 7.5 m/s

• Accelerates at 0.5 m/s²

We have to use the third equation of motion to find the distance travelled:-

$\sf\dashrightarrow \: s = ut + \dfrac { 1 } { 2 } \times { at }^{ 2 }$

$\sf\dashrightarrow \: s = 7.5 \times 12 + \dfrac { 1 } { 2 } \times 0.5 \times 144$

$\sf\dashrightarrow \: s = 90 + ( 0.5 \times 72$

$\sf\dashrightarrow \: s = 90 + 36$

$\sf\dashrightarrow \: s = 126 \: m$

Hence ,

• Distance travelled by train in 12 seconds is 126m.