Question

A train travelling at 27km/h is accelerated at the rate of 0.5m/s^2.what is the distance travelled by the train in 12 seconds.​

Answer 1

Given:-

Speed of train or initial velocity = 27 km/h

Acceleration of the train = 0.5 m/s²

Total time taken by train = 12 s

To Find:-

Distance travelled by train in 12s = ?

Solution:-

To calculate the distance travelled by train , at first we have to change the initial velocity into m/s then we use a formula to calculate the distance travelled by train. We use second equation of motion.

Formula Used:-

==> S = u t + 1/2 a t²

==> Initial velocity = 27 × 5/18

==> Initial velocity = 15/2 m/s

Let's Find out distance here:-

As per 2nd equation of motion:-

==> S = Ut + 1/2 a t²

S = Distance , t = Time, U = initial velocity

==> S = 15/2 × 12 + 1/2 × 0.5 × (12)²

==> S = 15 × 6 + 1/2 × 0.5 × 12 × 12

==> S = 90 + 0.5 × 6 × 12

==> S = 90 + 0.5 × 72

==> S = 90 + 36

==> S = 126 m

Hence,

Distance travelled by train in 12s= 126 m

Answer 2

Answer:

hope it help you.

good morning.