A train travelling at 27km/h is accelerated at the rate of 0.5m/s^2.what is the distance travelled by the train in 12 seconds.
Answers
Given:-
Speed of train or initial velocity = 27 km/h
Acceleration of the train = 0.5 m/s²
Total time taken by train = 12 s
To Find:-
Distance travelled by train in 12s = ?
Solution:-
To calculate the distance travelled by train , at first we have to change the initial velocity into m/s then we use a formula to calculate the distance travelled by train. We use second equation of motion.
Formula Used:-
==> S = u t + 1/2 a t²
==> Initial velocity = 27 × 5/18
==> Initial velocity = 15/2 m/s
Let's Find out distance here:-
As per 2nd equation of motion:-
==> S = Ut + 1/2 a t²
S = Distance , t = Time, U = initial velocity
==> S = 15/2 × 12 + 1/2 × 0.5 × (12)²
==> S = 15 × 6 + 1/2 × 0.5 × 12 × 12
==> S = 90 + 0.5 × 6 × 12
==> S = 90 + 0.5 × 72
==> S = 90 + 36
==> S = 126 m
Hence,
Distance travelled by train in 12s= 126 m
Answer:
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