Question

A train travelling at 30 ms -1. accelerates at 0.5ms-1 for 30s. How far will it travel in his time​

Answer 1

Given:-

• Initial velocity ,u = 30m/s
• Acceleration ,a = 0.5m/s²
• Time taken ,t = 30s

To Find:-

• Distance covered by train ,s

Solution:-

According to the Question

It is given that train travelling at 30 ms -1. accelerates at 0.5ms-1 for 30s. we have to calculate the distance covered by train in the given time interval.

So by using 2nd equation of motion

• s = ut +1/2at²

where,

• s is the distance covered
• a is the acceleration
• u is the initial velocity
• t is the time taken

Substitute the value we get

$\longrightarrow$ s = 30×30 + 1/2×(0.5) × 30²

$\longrightarrow$ s = 900 + 1/2 × 0.5 × 900

$\longrightarrow$ s = 900 + 0.5×450

$\longrightarrow$ s = 900 + 225

$\longrightarrow$ s = 1125 m

• Hence, the distance covered by train at given time interval is 1125 metres or 1.125 Km.

Answer 2

Answer:

According to the Question

It is given that train travelling at 30 ms -1. accelerates at 0.5ms-1 for 30s. we have to calculate the distance covered by train in the given time interval.

So by using 2nd equation of motion

s = ut +1/2at²

where,

s is the distance covered

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

$\longrightarrow⟶ s = 30×30 + 1/2×(0.5) × 30²$

$\longrightarrow⟶ s = 900 + 1/2 × 0.5 × 900$

$\longrightarrow⟶ s = 900 + 0.5×450$

$\longrightarrow⟶ s = 900 + 225$

$\longrightarrow⟶ s = 1125 m$

The distance covered by train at given time interval is 1125 metres or 1.125 Km.