Question

A train travelling at 30 ms -1. accelerates at 0.5ms-1 for 30s. How far will it travel in his time​

Answer 1

Answer:

The required answer is 1125 m

Explanation:

Given :

A train travelling at 30 m/s accelerates at 0.5 m/s² for 30 s.

To find :

the distance travelled

Solution :

initial velocity, u = 30 m/s

acceleration, a = 0.5 m/s²

time taken, t = 30 s

distance travelled, s = ?

Using  $\bf s=ut+\dfrac{1}{2}at^2$,

$\rm s=30(30)+\dfrac{1}{2}(0.5)(30^2) \\\\ \rm s=900+\dfrac{900}{4} \\\\ \rm s=900+225 \\\\ \rm s=1125 \ m$

Therefore, the distance travelled is 1125 m.

Answer 2

1125 m (1.125 km)

Explanation:

Given -

A train travelling at 30 m/s, accelerates at 0.5 m/s² for 30s. How far will it travel in this time ?

Solution -

From the given question we can say,

initial speed (u) = 30 m/s

Acceleration (a) = 0.5 m/s²

Time taken (t) = 30 s

Distance traveled (s) = ?

Using formula,

$\sf \: s = ut + \frac{1}{2} a {t}^{2}$

we can find the distance.

[put the value of u, t and a]

$\sf = > s = (30 \times 30) + ( \frac{1}{2} \times 0.5 \times 3 {0}^{2} ) \\ \\ = > \sf 900 + ( \frac{1}{ \cancel{2} } \times \frac{1}{ \cancel{2}} \times \cancel{30}^{15} \times { \cancel{30}}^{15} ) \\ \\ = > \sf900 + (15 \times 15) \\ \\ = > \sf900 + 225 \\ \\ = > \sf1125 \: m$

Hence the train will travel 1125 metres in this time.

hope it helps.