Question

a train travelling at 30km/h is brought to rest at a station in 1.5 min. the distance frim the station where the brakes were applied is

Answer 1

hey dear
here is your answer

given datra :

initial velocity (u) = 30 km/hr or 8.33 m/s

final velocity (v) = 0

time (t) = 1.5 min. or 90 seconds

to find : acceleration (a) & distabnce covered (s)

here we go

solution : for acceleration

by using first equation of motion

v = u+at

0 = 8.33+90a

90a = -8.33

a = -0.092 m/s²

solution : for distance

by usding third equation of motion

v² = u²+2as

0 = (8.33)²+2*(-0.092)*s

69.38 = 0.184s

s = 377 meter

hope it helps :)