Question

A train travelling at 30m/s accelerates at 0.5m per second square for 30s how far will it travel in this time​

Answer 1

Answer:

Initial velocity, u=20m/s

Time, t=30s

Acceleration,

a=0.5m/s

2

Distance travelled is:

s=ut+

2

1

at

2

s=20×30+

2

1

×0.5×30×30

s=600+225=825m

Answer 2

${\large{\bf{\underline{\underline{→Given {}}}}}}$

• Initial Velocity of train = 30m/s
• Acceleration = 0.5m
• Total Time taken = 30 s

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${\large{\bf{\underline{\underline{→To \: Find{}}}}}}$

• Distance travelled In given time

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${\large{\bf{\underline{\underline{→ Solution {}}}}}}$

FOR SOLVING THE ABOVE QUESTION

WE HAVE TO USE

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[FIRST EQUATION OF MOTION ]

${\small{\bf{\underline{\underline{{v= u + at}}}}}} \\ </u></strong></p><p><strong><u> {\small{\bf{\underline{\underline{{v = 30 + 0.5 \times 30 }}}}}} \\ {\small{\bf{\underline{\underline{{v = 30 + 15}}}}}} \\ {\small{\bf{\underline{\underline{v = 45{}}}}}}$

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• FOR FINDING FINAL SOLUTION

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[THIRD EQUATION OF MOTION]

${\small{\bf{\underline{\underline{{v² = u²+2as}}}}}} \\ {\small{\bf{\underline{\underline{{ {45}^{2} = {30}^{2} + 2 \times 0.5 \times 5}}}}}} \\ {\small{\bf{\underline{\underline{{ 2025 = 900 + 2 \times 0.5 \times s}}}}}} \\ {\small{\bf{\underline{\underline{{2025 - 900 = s}}}}}} \\ {\small{\bf{\underline{\underline{{s = 1125}}}}}}$

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• Therefore the distance travel By train is

= 1,125