A train travelling at 36 km/h speeds up to 72 km/h in 10 seconds. What is the acceleration of the train in S.I unit?
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Initial velocity u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s Final velocity v = 72 km/h = 72 x 1000/3600 m/s = 20 m/s Time t = 10 s Acceleration a = (v-u)/t = (20 - 10)/10 = 1 m/s2.
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