Question

A train travelling at 36km/have access template unit formal at 2m/s2 cal. It velocity after 5 sec​

Answer 1

Answer:

v=20m/s

Explanation:

Given-

u=36km/h

=36×5/18

=10m/s

a=2m/s^2

t=5sec

v=?

v=u+at

v=10+2×5

v=20m/s