Math, asked by Manjeetsingh11, 1 year ago

A train travelling at 48 km per hr crosses another train having half it's its length and travelling in opposite direction at 42 km per hour in 12 second it also pass is a railway platform in 45 seconds the length of platform is ???

Answers

Answered by leo15
9
let x and y represent the longer and the shorter train respectively

speed of x = 48 km/h
speed of y = 42 km/h
time taken for x to cross y = 12 s
length of the longer train = relative speed of x and y × time
= (48 km/h - 42 km/h) × 12 s
= 6 km/h × 12 s
= 6 km/h × 12 / 3600 h
= 0.02 km
= 20 m
and length of y = 1/2 × length of x
= 1/2 × 20 m
= 10 m

now,
length of platform = 42 km/h × 12 s
= 48 km/h × 45/3600 h
= 0.6 km
= 600 m

Manjeetsingh11: wow thanks
leo15: is it correct
Manjeetsingh11: yes of course
Manjeetsingh11: but i have a doubt on the length of train
leo15: what kind of doubt
Manjeetsingh11: length of train is correct
leo15: thanks
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