A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is
A.400 m
B.450 m
C. 560 m
D.600 m
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Answer: Option A
Explanation:
Let the length of the first train be x metres.
Then, the length of the second train is xmetres.2
Relative speed = (48 + 42) kmph =90 x5m/sec = 25 m/sec.18
[x + (x/2)]= 12 or3x= 300 or x = 200.252
Length of first train = 200 m.
Let the length of platform be y metres.
Speed of the first train =48 x5m/sec =40m/sec.183
(200 + y) x3= 4540
600 + 3y = 1800
y = 400 m.
Explanation:
Let the length of the first train be x metres.
Then, the length of the second train is xmetres.2
Relative speed = (48 + 42) kmph =90 x5m/sec = 25 m/sec.18
[x + (x/2)]= 12 or3x= 300 or x = 200.252
Length of first train = 200 m.
Let the length of platform be y metres.
Speed of the first train =48 x5m/sec =40m/sec.183
(200 + y) x3= 4540
600 + 3y = 1800
y = 400 m.
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