Question

A train travelling at 54km/h accelerate uniformly at 2m/s for 1/4 minute, find the distance in this time

Answer 1

Answer:

First convert speed in m/s

$54 \: kmph = 54 \times \frac{5}{18} \frac{m}{s} = 15 \: \frac{m}{s}$

$\frac{1}{4} \: min = \frac{1}{4} \times 60 \: s = 15 \: s$

Now

$s = ut + \frac{1}{2} a {t}^{2} \\ \\ s = 15(15) + \frac{1}{2} \times 2 ( {15}^{2} ) \\ \\ s = 450 \: m$