Question

A train travelling at 55 ms has to reduce speed to 35 ms to pass
to pass through a junction. If the
deceleration does not exceed 0.6 ms-1, how far ahead of the junction should the train begin
to slow down ?​

Answer 1

Explanation:

By using 3rd equation of kinematics,

v^2= u^2 - 2as -(I)

here

v=final velocity , u=initial velocity, a=declaration, s=displacement

we have to calculate "s".

so from given data from the question & the equation I we get

s= -(v^2 - u^2)÷2a

s= -(35^2 - 55^2)÷2*0.6

s= 1500m

so the train should begin to slow down before 1500m.