a train travelling at 72 km per hour is stopped in 4 seconds by the application of brakes what is the retardation of the train
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Answered by
10
v = u - a×t
0 = 72×5/18 - a×4
4a = 20
a = 5m/s^2
0 = 72×5/18 - a×4
4a = 20
a = 5m/s^2
Answered by
3
72-0/4=1=18km/sec retardation
Iamkeetarp:
bro time is given in seconds...
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