Question

A train travelling at a speed of 20 m/s along a straight line slows down at a uniform rate and stops in 40 s .calculate in acceleration and distance moved in that time

Answer 1

Answer:

v=u+at here v is zero ,u= 20m/sec and t is 40 sec ,, 0=20+a×40 ,,-20/40=a ,a= -0.5 m/sec^2 ,, S=ut+1/2at^2 ,,S=20×40 +1/2 (-0.5)×40×40 , S=800-400 ,,S=400 m ans