A train travelling at a speed of 90km/h .Brakes are applied so as to produce a uniform acceleration of -0.5m/s square .Findhow far the tarin will go before it is brought to rest
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V^2= U^2 - 2aS
V = Final velocity. Which in this case, 0.
U= Initial Velocity.ie, 10 m/s.
a= acceleration. Here, -2 m/s^2.
S= the required distance to stop.
The equation becomes,
0= U^2- 2aS.
U^2= 2aS.
S= U^2/ 2a.
= 10^2/ 2×2.
100/4
= 25 mts.
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