Question

A train travelling at a uniform speed for 350 km, would have taken 1 hour 10 min less to travel the same distance if speed was increased by 10 km/hr. Then find its original speed​

Answer 1

Answer:

x=45

Step-by-step explanation:

Let x= Original Speed

we know that

distance= time

speed

So as per the question the following equation can be formed

360− 360= 48

x x+5 60 [1 hour = 60 minutes]

⇒ 1 - 1 = 48 . 1

x x+5 60 360

⇒ 5 = 1

x^2 + 5x 450

⇒x^2+5x−2250=0

⇒x^2−45x+50x−2250=0

⇒x(x−45)+50(x−45)=0

⇒(x−45)(x+50)=0

x=45,−50

As the speed can't be negative so,

x=45

MARK ME AS BRAINLIST.....

Answer 2

Original Speed = 50 km/hr if a train takes 1 hr 10 mins less to travel 350 km in case speed is increased by 10 km/hr

Given:

• A train travelling at a uniform speed  for 350 km
• Take  1 hour 10 min less to travel the same distance if speed  increased by 10 km/hr

To Find:

• Original Speed

Solution:

• Distance = Speed x Time

Step 1:

Assume that Original Speed is  x km/hr

Hence increased speed = x + 10 km/hr

Step 2:

Calculate time taken with Speed x km/hr and Distance = 350 km

Time = 350/x   hr

Step 3:

Calculate time taken with Speed x+10 km/hr and Distance = 350 km

Time = 350/(x+10)   hr

Step 4:

Equate the time difference with 1 hr 10 mins = 1 + 10/60  = 7/6 hrs and solve for x

350/x  -  350/(x+10)  = 7/6

=> 300/x  - 300/(x + 10) = 1

=> 300(x + 10 - x) = x(x + 10)

=> 3000 = x² + 10x

=> x² + 10x - 3000 = 0

=> x² + 60 x - 50x  - 3000 = 0

=> (x + 60)(x - 50) = 0

=> x = 50  only        ( speed can not be negative)

Original Speed = 50 km/hr