A train travelling at a uniform speed for 360 km would have taken 48 minutes less
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Answered by
15
Answer:
Let original speed of the train be x km/h.
Time taken at original speed = 360/x hours
Time taken at increased speed = 360/(x+5) hours
Now, 360/x - 360/(x+5) = 48/60
360[1/x - 1/(x+5)] = 4/5
x2 + 5x – 2250 = 0
x = 45 or –50
As speed cannot be negative
x = 45 km/h
Answered by
0
Answer:
minutes less to travel the same distance if its speed were 5 km/hour more.
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