A train travelling at a uniform speed for 360 km would have taken 48 minutes less to travel the same distance if its speed where 5 km per hour more. Find the original speed of train a
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Answer:
Step-by-step explanation:
Solution :-
Let the original speed of the train be x km/h
Time taken at original speed = 360/x km/h
Time taken at increased speed = 360/x + 5 km/h
According to the Question,
⇒ 360/x - 360/x + 5 = 48/60
⇒ 360(1/x - 1/x + 5) = 4/5
⇒ x² + 5x - 2250 = 0
⇒ x² - 45x + 50x - 2250 = 0
⇒ x(x - 45) + 50(x - 45) = 0
⇒ (x - 45)(x + 50) = 0
⇒ x = 45 , - 50 (Speed cannot be negative)
⇒ x = 45 km/h
Hence, The original speed of train is 45 km/h.
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