A train travelling at a uniform speed for 360 km would have taken 48 minutes less to
travel the same distance if its speed were 5 km/hour more. Find the original speed of
the train. !!please fast !!
Answers
Answered by
0
equation ............360/s -360/[s+5]=48/60
s^2+5s=2250
answer...45 km/h
s^2+5s=2250
answer...45 km/h
Answered by
1
time taken=48/60 hours=4/5hrs
360/x -360/x+5=4/5
360(x+5)-360x/x²+5x=4/5
360x-360x+1800/x²+5x=4/5
1800x5/4=x²+5x
450x5=x²+5x
x²+5x-2250=0
-b ±√b²-4ac/2a
-5±√25-(-2250x4x1)/2
-5±√9025/2
-5±120/2
-120-5/2 ,115/2
57.5 kmph=speed
360/x -360/x+5=4/5
360(x+5)-360x/x²+5x=4/5
360x-360x+1800/x²+5x=4/5
1800x5/4=x²+5x
450x5=x²+5x
x²+5x-2250=0
-b ±√b²-4ac/2a
-5±√25-(-2250x4x1)/2
-5±√9025/2
-5±120/2
-120-5/2 ,115/2
57.5 kmph=speed
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