a train travelling at a uniform speed for 360 km would have taken 48 minutes less to travel the same distance if its speed wear 5 km per hour more find its original speech of the train
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let original speed of train = x km/h ↓
.we know, time = distance/speed
.first case ———————time taken by train = 360/x hour ↓
.second case —————————— ↓
.time taken by train its speed increase 5 km/h = 360/( x + 5)
question says that :↓
.time taken by train in first - time taken by train in 2nd case = 48 min = 48/60 hour
360/x - 360/(x +5) = 48/60 = 4/5
360{ 1/x - 1/(x +5) } = 4/5
360 ×5/4 { 5/(x² +5x )} =1
450 x 5 = x² + 5x
x² +5x -2250 = 0
x = { -5±√(25+9000) }/2 =(-5 ±√(9025) )/2 =(-5 ± 95)/2 = -50 , 45 ↓
.but x ≠ -50 because speed doesn't negative
so, x = 45 km/h __________________________________________________________hence, original speed of train = 45 km/h
Hope it helps mark as brainliest
=======================================================
let original speed of train = x km/h ↓
.we know, time = distance/speed
.first case ———————time taken by train = 360/x hour ↓
.second case —————————— ↓
.time taken by train its speed increase 5 km/h = 360/( x + 5)
question says that :↓
.time taken by train in first - time taken by train in 2nd case = 48 min = 48/60 hour
360/x - 360/(x +5) = 48/60 = 4/5
360{ 1/x - 1/(x +5) } = 4/5
360 ×5/4 { 5/(x² +5x )} =1
450 x 5 = x² + 5x
x² +5x -2250 = 0
x = { -5±√(25+9000) }/2 =(-5 ±√(9025) )/2 =(-5 ± 95)/2 = -50 , 45 ↓
.but x ≠ -50 because speed doesn't negative
so, x = 45 km/h __________________________________________________________hence, original speed of train = 45 km/h
Hope it helps mark as brainliest
=======================================================
Answered by
2
Here's your answer....
45km/hr..
Thank You!....
Hope it helps..
45km/hr..
Thank You!....
Hope it helps..
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