Math, asked by Deepalijindal, 1 year ago

a train travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were by 5 km/hr more. find the original speed of the train.
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Answers

Answered by shahnad
1
45 km/hr

take speed as xkm/h

therfore eq. is  360/x -360/x+5=48/60  (time has to be converted from 48 min to 48/60 hr)

on solving we get,  1800/ Xsq. + 5=4/5  =Xsq. +5X-2250=0

so x=45 or x=-50(discarded)
  hence speed of train=45km/hr

Answered by chandresh126
3
Hey DeepaliJindal,

Here ur answer.

Let original speed of the train be x km/h.

Time taken at original speed = 360/x hours

Time taken at increased speed = 360/(x+5) hours

Now, 360/x - 360/(x+5) = 48/60

360[1/x - 1/(x+5)] = 4/5

x2 + 5x – 2250 = 0

x = 45 or –50

As speed cannot be negative

x = 45 km/h

Hope it will be Help uh.

Thank-you.

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