a train travelling at a uniform speed for 6900 km would have taken 9 hours less to travel the same distance if its speed were 15 kilometre per hour more find the original speed of the train
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Answer:
45 km/hr
take speed as xkm/h
therefore eq. is 360/x -360/x+5=48/60 (time has to be converted from 48 min to 48/60 hr)
on solving we get, 1800/ Xsq. + 5=4/5 =Xsq. +5X-2250=0
so x=45 or x=-50(discarded) hence speed of train=45km/hr
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