Question

A train travelling at a uniform speed of 360km/hr would have taken 48 minutes less to travell the same distance if its speed is 5km/hr more. find the original speed of the train

Answer 1

original speed of train =x
time taken=360\x+5
=48/60
90(x+5-x/x(x+5))=4/5
90(5)5=x×x+5x
x×x+5x-2250=0
therefore speed=45km ph

Answer 2

Answer:

original speed of train =x

time taken=360\x+5

=48/60

90(x+5-x/x(x+5))=4/5

90(5)5=x×x+5x

x×x+5x-2250=0

therefore speed=45km ph