Question

A train travelling at the speed of x km/h crossed a 200 m long platform in 30 seconds and overtook a man walking in the same direction at the speed of 6 km/h in 20 seconds.

Answer 1

Answer:

by condition

(200+y)/30=x.........y= length of train

200+y=30x

30x-y=200------1

also by 2nd condition

y/(x-6)=20

y=20x-120

20x-y=120------2

eq 1-2

10x=80

x=10m/s