a train travelling at uniform speed for 360km would have taken 48 mins less to travel same distance if it's speed were 5km/hr. find speed
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let sp. of train be x km/h
nd distance be y km/h
we know,
time = d/s
Case1:
Time taken by train = 360/x hour
Case2:
Time taken by train its speed = 360/( x + 5)
360/x - 360/(x +5) = 48/60 = 4/5
360[ 1/x - 1/(x +5) ] = 4/5
360 ×5/4 [ 5/(x² +5x )] =1
450 x 5 = x² + 5x
x² +5x -2250 = 0
x = { -5±√(25+9000) }/2
=(-5 ±√(9025) )/2
=(-5 ± 95)/2
= -50 , 45
Since x ≠ -50 spd cant be -ve
Thus, x = 45 km/h
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